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Any HM's have a birthday while theyre in the house?
bigfredman
03-06-2004
Does anyone know whether any of housemates birthdays are during BB??? Hope so lots of booze
RKO'd
03-06-2004
I heard none of them have birthdays for the entire 71 days
Hamlet77
03-06-2004
No, so no chance of jelly and ice cream either. Boo Hoo
Dykeolicous
03-06-2004
It's become tradition for a HM to have a b/day. But then this is Evil BB
Scissor*Sister
03-06-2004
No birthdays,
metafis
03-06-2004
what are the odds on that then?
anyone good at calculating the odds?.
klunk
03-06-2004
About a 1 in 14 chance of it happening, I make it. Unlikely, but not that unlikely.
licktap
03-06-2004
Quick calculation shows that for 10 weeks it would be evens money if there were just 4 in the house. With 12 in the house I think the odds are 0.084 (about 25:2 against).

I think, also, the chances of 12 people sharing the exact same birthday are about 5:1 against.
afcbfan
03-06-2004
Originally Posted by klunk:
“About a 1 in 14 chance of it happening, I make it. Unlikely, but not that unlikely.”

The odds of two people sharing the same birthday in a group of 23 people is 50/50, apparently. Not sure about the odds of 12 people not having a birthday in a 10 week period, though. Sorry
Mister Al
03-06-2004
71 days in the house, so the probability of any housemate having a birthday during that period is 71/365. And the probability of them not having a birthday is 294/365.

Multiply that by itself twelve times for the twelve housemates and you get...

417030640378345864542952820736/5591320323850160818242431640625

...or, 0.075 to three decimal places. A 7.5% chance then. About 1 in 13.4, if you prefer.

Of course, this doesn't take into account leap years, but I think it's probably close enough...
Exocet
04-06-2004
Originally Posted by Mister Al:
“71 days in the house, so the probability of any housemate having a birthday during that period is 71/365. And the probability of them not having a birthday is 294/365.

Multiply that by itself twelve times for the twelve housemates and you get...

417030640378345864542952820736/5591320323850160818242431640625

...or, 0.075 to three decimal places. A 7.5% chance then. About 1 in 13.4, if you prefer.

Of course, this doesn't take into account leap years, but I think it's probably close enough...”

It does make a slight difference if you include leap years. Just change the lower commen denominator to 365.25

Therefore the chances of no HM's having a birthday in the house reduces to 7.4%

Pedantic .... moi ?
Exocet
04-06-2004
Originally Posted by afcbfan:
“The odds of two people sharing the same birthday in a group of 23 people is 50/50, apparently. Not sure about the odds of 12 people not having a birthday in a 10 week period, though. Sorry ”

Actually the chances of two people in a room full of 23 people sharing the same birthday is 51%, therefore more than 50:50

The chances of the big brother housemates sharing the same birthday (12 people) is approx 18% or close enough to 1 in 5
Juliana
04-06-2004
Where's Carol Voderman when you need her.
Mister Al
04-06-2004
Originally Posted by Exocet:
“The chances of the big brother housemates sharing the same birthday (12 people) is approx 18% or close enough to 1 in 5”

Actually, the chances of twelve people all sharing the same birthday is 1 in 5591320323850160818242431640625.

Maybe you meant the chances of two people out of twelve sharing a birthday, in which case the chances are (again assuming a 365 day year)...

102344010566252155325086877/612747432750702555423828125

...or 16.7%. Much closer to 1 in 6 than to 1 in 5.

I'll out-pedant the lot of you!

(Oh, and Carol who? Didn't she only get a Third or something...?)
Exocet
04-06-2004
Originally Posted by Mister Al:
“Actually, the chances of twelve people all sharing the same birthday is 1 in 5591320323850160818242431640625.

Maybe you meant the chances of two people out of twelve sharing a birthday, in which case the chances are (again assuming a 365 day year)...

102344010566252155325086877/612747432750702555423828125

...or 16.7%. Much closer to 1 in 6 than to 1 in 5.

I'll out-pedant the lot of you!

(Oh, and Carol who? Didn't she only get a Third or something...?)”



Yes that's what I meant ... remind me not to play Black Jack against you - I bet your a cardcounter
klunk
04-06-2004
If you're going to start nitpicking, what about the fact that birthdays are not evenly distributed throughout the year? I'll expect a new calculation, taking this into account, on my desk first thing Monday morning .
zzenzero
04-06-2004
Not to worry,folks,Russell Brand and Dermot are having birthdays.These geminis are everywhere.
davienicholl
04-06-2004
Vanessa almost has...her b/day is 12th august
Mister Al
04-06-2004
Originally Posted by klunk:
“If you're going to start nitpicking, what about the fact that birthdays are not evenly distributed throughout the year? I'll expect a new calculation, taking this into account, on my desk first thing Monday morning .”

Excellent pedantry skills there, Klunk. You have my respect.
Exocet
04-06-2004
Originally Posted by klunk:
“If you're going to start nitpicking, what about the fact that birthdays are not evenly distributed throughout the year? I'll expect a new calculation, taking this into account, on my desk first thing Monday morning .”

The best figures I could get were Average Daily Birth Frequencies in the United States, 1978-1987
Month Daily Frequency
January .0026123
February .0026785
March .0026838
April .0026426
May .0026702
June .0027424
July .0028655
August .0028954
September .0029407
October .0027705
November .0026842
December .0026864


The month-to-month variation of births is sufficiently small that match probabilities barely change from those calculated by assuming a uniform distribution. I cannot see any reason UK births would have much varience from their U.S. counterparts

References:

Diaconis, P., and F. Mosteller. 1989. Methods for studying coincidences. Journal of the American Statistical Association 84(December)

Source:
http://www.maa.org/mathland/mathtrek_11_23_98.html
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