Solve this equation > 48÷2(9+3) = ? |
| View Poll Results: Which is right? | |||
| 2 |
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663 | 55.76% |
| 288 |
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526 | 44.24% |
| Voters: 1189. You can't vote on this poll right now - are you signed in? | |||
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#1427 |
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#1428 |
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http://i53.tinypic.com/2jb4qjd.jpg <-- winnar
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#1430 |
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#1431 |
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If there is no ambiguity, why do Excel, python, sql+, ms foxpro all flag it up as an error requiring correction?
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#1432 |
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Exactly as in the first post, my other three scientific calculators get 2. With the * put in, they all get 288.
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#1433 | |
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Quote:
I find it out that wolfram gave a diffrent answer with 1/2x and 1/2*x. almost as if they were not the same. |
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#1434 |
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#1435 | |
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Quote:
x * (z + y) is not the same as x(z +y) when used in an expression/equation. |
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#1436 | |
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Quote:
2(9+3) is a factorised shorthand of (2.9+2.3). |
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#1437 |
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Totally agree.
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#1438 |
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http://www.physicsforums.com/showthr...=488334&page=8
50:50 split. Solved by singer/gagwoman Kwak Hyun Hwa, who’s also a mathematics graduate from the prestigious Ewha Women’s University, http://www.allkpop.com/2011/04/kwak-...to-48%C3%B7293 !!!!!! ,,,,wait, no it isn't ![]() what's a gagwoman? |
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#1439 |
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#1441 | |
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Quote:
48÷(2x(9+3) = 48/(2x(9+3) = 48÷(2*(9+3) = 48/(2*(9+3) = 48÷(2(9+3) = 48/(2(9+3) = 2 (48÷2)x(9+3) = (48/2)x(9+3) = (48÷2)*(9+3) = (48/2)*(9+3) = (48÷2)(9+3) = (48/2)(9+3) = 288 The only relevant factor here is the ORDER of operations! The symbol used for the operators have absolutely no bearing whatsoever on their function, and I find it difficult to believe anyone can seriously be suggesting otherwise! It’s simply done in an attempt to support a flawed argument. |
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Quote:
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My TI-83 gives 288 for 48/2(9+3).
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#1444 |
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Exactly. Like I said pages ago the 2 has to be taken as part of the bracket removing process to give the 24 to divide into the 48 giving your answer of 2
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#1445 |
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#1446 |
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#1447 |
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#1448 |
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#1449 | |
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I don't suppose for one second they thought that anyone would make any assumptions from that. Yes that was quite funny... |
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#1450 | |
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Quote:
Y(b + c) = (Yb + Yc) Y times (b + c) = Y * (b +c) = Y x (b +c) The * or times sign means that the Y never goes inside the bracket, Y next to a bracket without an other operator means that the Y is part of the bracket (e.g. it is a factorial, etc.) |
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