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The Chase (ITV) (Part 4) |
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#626 |
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Join Date: Mar 2014
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Maybe he's been threatened with the sack cos he's always losing money?
Or more likely he's got the flu or something. |
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#627 |
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Join Date: Oct 2004
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Shaun shaking badly
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#628 |
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Join Date: Sep 2011
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Les Dennis and Sinitta on the celeb special tomorrow.
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#629 |
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Join Date: Oct 2011
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Why did he waste like 15 seconds on one question and how did he get that Winnie the Pooh question wrong?!
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#630 |
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Join Date: May 2010
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Did they score 18?
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#631 |
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Quote:
Did they score 18?
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#632 |
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Quote:
Gosh Shaun is shaking badly now. Hope he doesn't have parkinsons.
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#633 |
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He wasted far too much time on the Imagination one, he hasn't learnt at all from making previous mistakes like this where he should just say 'pass' if the answer doesn't come to him within a couple of seconds.
Like others have said I did notice that his shaking was very noticeable in Final Chase and do hope that he is ok. |
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#634 |
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Quote:
Gosh Shaun is shaking badly now. Hope he doesn't have parkinsons.
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#635 |
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Glad Lisa got the Big Bang Theory pushback question right.
She looked so chuffed to get something for the team in the final, and they all congratulated her. |
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#636 |
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Quote:
Apparently she's supposed to be dressed up as Sailor Moon.
So ITV are allowing cosplayers on quiz shows now? ![]() |
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#637 |
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I don't understand. Did ITV have a ban on cosplayers before?
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#638 |
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Quote:
Glad Lisa got the Big Bang Theory pushback question right.
She looked so chuffed to get something for the team in the final, and they all congratulated her. Quite often when there's four in the Final Chase, at least one of them hardly answers any,or, as in this case, none at all. It's not really that surprising when you think about it. If it's a relatively easy question, one of the stronger players will know it and buzz in first. And if it's a more difficult question, that none of the stronger players know, the chance that the weakest player will be the only one that knows it is really quite small. Consider a hypothetical team in which Player A, the strongest, knows the answer 50% of the time, Player B, 40%, Player C, 30% and the weakest, Player D, who knows the answer only 20% of the time. Obviously these probabilities are somewhat arbitrary,but anyway, let's ask: What is the chance that Player D knows the answer, and none of the other three do? It is only four per cent. In other words probably only one question in the Final Chase. Maybe two. Add in their point for being there and that makes two or maybe three.. But then factor in the chance that the weakest player, understandably getting frustrated at not answering any questions, buzzes in early with a pass or a wrong answer. That could easily cost the team a point or two. I would reckon the weakest player in a team of four is only worth on average two points at most - and that's including their one point for being there. Of course I could be completely wrong.
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#639 |
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Are you sure it's not your telly? I was looking closely and didn't detect any shaking.
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#640 |
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Yes but I don't think she answered any their Final Chase. and they were so far ahead then that they would have won anyway even if they hadn't got that pushback.
Quite often when there's four in the Final Chase, at least one of them hardly answers any,or, as in this case, none at all. It's not really that surprising when you think about it. If it's a relatively easy question, one of the stronger players will know it and buzz in first. And if it's a more difficult question, that none of the stronger players know, the chance that the weakest player will be the only one that knows it is really quite small. Consider a hypothetical team in which Player A, the strongest, knows the answer 50% of the time, Player B, 40%, Player C, 30% and the weakest, Player D, who knows the answer only 20% of the time. Obviously these probabilities are somewhat arbitrary,but anyway, let's ask: What is the chance that Player D knows the answer, and none of the other three do? It is only four per cent. In other words probably only one question in the Final Chase. Maybe two. Add in their point for being there and that makes two or maybe three.. But then factor in the chance that the weakest player, understandably getting frustrated at not answering any questions, buzzes in early with a pass or a wrong answer. That could easily cost the team a point or two. I would reckon the weakest player in a team of four is only worth on average two points at most - and that's including their one point for being there. Of course I could be completely wrong. ![]() |
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#641 |
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Join Date: Jan 2014
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Anyone who goes to pub quizzes will know that big teams don't guarantee success. I have seen teams with seven, eight, even nine people in them. (Some quizzes have a five or six player maximum number, but some don't). They hardly ever win. In a team of nine, there will probably be three people actually doing the quiz, three chipping in with the odd (hopefully right) answer, and three who are no help at all and are only there for the beer. Look for the person with the pen writing down the answers - they're in charge. The further away you are from the pen, the less and less influence you have on what gets written down. The person furthest from the pen has next to none.
Most serious teams that go to our local pub quiz have no more than four members, and some have only three. |
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#642 |
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Quote:
Anyone who goes to pub quizzes will know that big teams don't guarantee success.
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#643 |
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I usually play in a pair and perform below average. But then at least one of us is quite thick.
"Jane has two children. At least one of them is a boy. What is the probability that the other one is also a boy?" Most people reason along these lines: "Well,it doesn't matter what the first child is, the second one is fifty fifty to be a boy as well, so the answer's fifty per cent." It sounds plausible - but it's wrong. In fact the chance that the second child is also a boy is only one third. If there are two children, there are four equally likely possibilities: boy/boy, boy/girl, girl/boy and girl/girl. The chance of having one of each sex is fifty percent. However we are told that at least one of them is a boy, so we can rule out girl/girl. That leaves us with three possibilities, only one of which is boy/boy. So the answer is one third or 33 and a bit percent. There is a long Wikipedia article on this (the "boy or girl paradox") if anyone's interested.
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#644 |
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Join Date: Jun 2002
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Shaun's shaking again. :/ I do hope it's not a symptom of a serious health issue.
![]() Is he ill with something? |
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#645 |
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Join Date: Jun 2002
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I've not really noticed but I'll watch more closely now to see what you mean.
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#646 |
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Join Date: Jun 2002
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Quote:
Apparently she's supposed to be dressed up as Sailor Moon.
So ITV are allowing cosplayers on quiz shows now? ![]() And why are you confused that they would? |
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#647 |
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Join Date: Apr 2010
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Two tweets from Shaun's twitter account about his shaking:
Shaun Wallace @TheShaunWallace 9h9 hours ago @silvertears123 no I was not feeling well during that block of filming but I've recovered now ![]() Shaun Wallace @TheShaunWallace 8h8 hours ago @BoxingAli71 i was I'll during that filming block I'm better now Glad to hear he's OK. |
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#648 |
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Join Date: Jun 2002
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That reminds me of the old probability problem that goes:
"Jane has two children. At least one of them is a boy. What is the probability that the other one is also a boy?" Most people reason along these lines: "Well,it doesn't matter what the first child is, the second one is fifty fifty to be a boy as well, so the answer's fifty per cent." It sounds plausible - but it's wrong. In fact the chance that the second child is also a boy is only one third. If there are two children, there are four equally likely possibilities: boy/boy, boy/girl, girl/boy and girl/girl. The chance of having one of each sex is fifty percent. However we are told that at least one of them is a boy, so we can rule out girl/girl. That leaves us with three possibilities, only one of which is boy/boy. So the answer is one third or 33 and a bit percent. There is a long Wikipedia article on this (the "boy or girl paradox") if anyone's interested. ![]() There are only three possibilities, not four. Boy/boy, girl/girl, and boy/girl. |
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#649 |
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Forum Member
Join Date: Jun 2002
Posts: 65,749
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Quote:
Two tweets from Shaun's twitter account about his shaking:
Shaun Wallace @TheShaunWallace 9h9 hours ago @silvertears123 no I was not feeling well during that block of filming but I've recovered now ![]() Shaun Wallace @TheShaunWallace 8h8 hours ago @BoxingAli71 i was I'll during that filming block I'm better now Glad to hear he's OK. Anyway, Matthew Wright, take note. ![]()
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#650 |
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Join Date: Jan 2014
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I don't see how that works, because boy/girl is exactly the same as girl/boy.
There are only three possibilities, not four. Boy/boy, girl/girl, and boy/girl. Think of it this way: first child boy,second child boy. Then first child boy, second child girl and first child girl, second child boy and finally first child girl, second child girl. A boy and a girl is twice as likely as either of the other two possibilities. Of all families with two children, half will have two boys or two girls, and half will have one of each. Another way to look at it is tossing two coins at the same time. What is the chance I get a Head and a Tail? If you say, "There's only three possibilities, two heads, two tails, or one of each, therefore it's two to one against", that's not correct. There are four possibilities: HH, HT, TH and TT, so fifty percent of the time you will get a Head and a Tail. If you don't believe me, you can try it. Just toss two coins about twenty or thirty times and see how many times you get one of each. You'll get a Head and a Tail about half the time. The more you do, the more your answer will get close to fifty percent. |
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