Originally Posted by Ken Tun:
“I'd have assumed that in consecutive letter rounds, but these were 6 or 7 games apart on different recordings.”
“I'd have assumed that in consecutive letter rounds, but these were 6 or 7 games apart on different recordings.”
I'm sure they were shuffled but not that well. What I was thinking of was poor shuffling allowing sets of 2 or 3 letters to "stick together", that would massively increase the chances of getting the same letters. Remember also that during the game they don't reuse the letters (or maybe they go on the bottom) meaning they may only be shuffled once.
Without that, just based upon chance it seems very unlikely to happen. I can't calculate the odds as I don't know how many of each letter there are but it will be a very big number against it happening. (I'm assuming the order was the same. i.e. a permutation rather than combination, there is a much much bigger chance of a same combination happening).
If it was random and there wasn't a limited number of cards then the chances of getting 2 deals the same given 6 consonants and 3 vowels would be 1 in around 10 billion much less than the chances of winning the lottery. The chances will be better than that because there is a limited number and there is not an even chance of each letter but even so the odds are bad. Also we have not specified which 2 deals are the same which greatly increases the chances but not enough.



